0.0825t^2-0.912t+1.793=0

Solution for 0.0825t^2-0.912t+1.793=0 equation:

0.0825t^2-0.912t+1.793=0

a = 0.0825; b = -0.912; c = +1.793;
Δ = b2-4ac
Δ = -0.9122-4·0.0825·1.793
Δ = 0.240054
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.912)-\sqrt{0.240054}}{2*0.0825}=\frac{0.912-\sqrt{0.240054}}{0.165}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.912)+\sqrt{0.240054}}{2*0.0825}=\frac{0.912+\sqrt{0.240054}}{0.165}
$